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Memory Allocation - 1 Memory Allocation - 2The ones who are crazy enough to think they can change the world are the ones who do.- Steve Jobs
C Array Tricky Questions
In most of the MNC interview questions such as in ZOHO interview question, IVTL Infoview interview questions, Amazon interview questions, GOOGLE interview questions, Infosys interview questions and even in Voonik interview questions, We come across several Tricky C Questions about which 2:5 of the questions are from Array in c. Solving that kind of tricky C questions is not an easy task for all C programmers. We need more practices to solve it with ease. So we provide 25+ interesting C questions in Array to make your MNC interview very easy.
C Array Questions
11. What will be the output of the C program?
#include<stdio.h>
int main()
{
int i = 0;
printf("Hello");
char s[4] = {'\b', '\t', '\r', '\n'};
for(i = 0;i<4;i++){
printf("%c", s[i]);
}
return 0;
}
x
Option: C
Explanation
Hello is printed followed by \b\t\r\n.
i.e) Hello\b\t\r\n.
i.e) Hell\t\r\n.
i.e) Hell \r\n.
i.e) Hell\n.
i.e) Hell is Outputted.
12. What will be the output of the C program?
#include<stdio.h>
int main()
{
static int a[ ] = {0, 1, 2, 3, 4};
int *p[ ] = {a, a + 1, a + 2, a + 3, a + 4};
int **ptr = p;
++*ptr;
printf("%d %d %d", ptr - p, *ptr - a, **ptr);
return 0;
}
x
Option: A
Explanation
*p[] is a pointer array variable which holds the all 5 addressess of a value in static integer array a[].
Our assumption
Address of 0 in a[] array is 4210692
Then a value of a in *p[] is 4210692 i.e) address of 0 in a[]
Now, the address of a in *p[] array is 2293416.
Our program explanation
**ptr = p;
**ptr = 0;
how **ptr =0?
**ptr = p;
**ptr= address of first element in p[];
We know that **ptr == *(*ptr)
then, *(*ptr) == *(*(address of first element in p[]))
*(*(address of first element in p[])) == *(value of first element in an array p[])
*(value of first element in an array p[]) == *(address of first element in an array a[])
*(address of first element in an array a[]) == value of first element in an array a[];
that is 0
What happens in ++*ptr;
we know that ++(*ptr) == ++(*(address of first element in p[]))
++(*(address of first element in p[])) == ++(value of first element in an array p[])
++(value of first element in an array p[]) == ++(address of first element in a[] which is address of 0)
++(address of first element in a[] which is address of 0) == address of second element in a[] which is address of 1
What happens in printf();
printf ("%d %d %d", ptr-p, *ptr-a, **ptr);
printf ("%d %d %d",2293416-2293416, *ptr-a, **ptr);
printf("%d %d %d", 0/(sizeof (int)), 4210696-4210692, **ptr);
printf("%d %d %d", 0, 4/(sizeof (int)), **ptr);
printf("%d %d %d", 0, 4/4, **ptr);
printf("%d %d %d", 0, 1, **ptr);
printf("%d %d %d", 0, 1, 1);
Thus 0 1 1 is outputted.
13. What will be the output of the C program?
#include<stdio.h>
int main()
{
int i = 0;
char s[4] = {'\0', '\0', '\0', '\0'};
for(i = 0;i<4;i++)
{
printf("%c", s[i]);
}
return 0;
}
x
Option: C
Explanation
\0 = NULL. Thus compiler prints nothing.
14. What will be the output of the C program?
#include<stdio.h>
int main()
{
char s[] = {'a', 'b', 'c', '\n', 'c', '\0'};
char *p, *str, *str1;
p = &s[3];
str = p;
str1 = s;
printf("%d", ++*p + ++*str1-32);
return 0;
}
x
Option: B
Explanation
p = &s[3].
i.e) p = address of '\n';
str = p;
i.e) str = address of p;
str1 = s;
str1 = address of 'a';
printf ("%d", ++*p + ++*str1 - 32);
i.e) printf("%d", ++\n + a -32);
i.e) printf("%d", 12 + 97 -32);
i.e) printf("%d", 12 + 65);
i.e) printf("%d", 77);
Thus 77 is outputted.
15. What will be the output of the C program?
#include<stdio.h>
int main()
{
int i = 0;
printf("Hello");
char s[4] = {'\b', '\r', '\t', '\n'};
for(i = 0;i<4;i++)
{
printf("%c", s[i]);
}
return 0;
}
x
Option: C
Explanation
Hello is printed followed by \b\r\t\n.
i.e) Hello\b\r\t\n.
i.e) Hell\r\t\n.
i.e) \t\n.
i.e) \n.
i.e) is Outputted.ie(8 space is outputted)
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