Pointers - C Questions
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Memory Allocation - 1 Memory Allocation - 2The ones who are crazy enough to think they can change the world are the ones who do.- Steve Jobs
C Pointers Tricky Questions and Answers
In most of the MNC interview questions such as in ZOHO interview question, IVTL Infoview interview questions, Amazon interview questions, GOOGLE interview questions, Infosys interview questions and even in Voonik interview questions, We come across several Tricky C Questions about which 2:5 of the questions are from pointers in c. Solving that kind of tricky C questions is not an easy task for all C programmers. We need more practices to solve it with ease. So we provide 25+ interesting C questions in pointers to make your MNC interview very easy.
Pointers Tricky Questions and Answers
21. What will be the output of the C program?
#include<stdio.h>
int main()
{
char *ptr;
char string[] = "learn C from 2braces.com";
ptr = string;
ptr += 6;
printf("%s",ptr);
return 0;
}
x
Option: D
Explanation
Each letter in string[] array is stored in seperate address. The starting address in string[] array is stored a pointer variable ptr which is then incremented by 6. Thus "learn " is neglected and "C from 2braces.com" is displayed.
22. What will be the output of the C program?
#include<stdio.h>
int main()
{
const int a = 5;
const int *ptr;
ptr = &a;
*ptr = 10;
printf("%d\n", a);
return 0;
}
x
Option: C
Explanation
Pointer variable *ptr cannot be initialized at any time.
23. What will be the output of the C program?
#include<stdio.h>
int main()
{
printf("%d", sizeof(void *));
return 0;
}
x
Option: D
Explanation
sizeof void is 1 and the sizeof void pointer is 4
24. What will be the output of the C program?
#include<stdio.h>
void function(char**);
int main()
{
char *arr[] = { "ant", "bat", "cat", "dog", "egg", "fly" };
function(arr);
return 0;
}
void function(char **ptr)
{
char *ptr1;
ptr1 = (ptr += sizeof(int))[-2];
printf("%s\n", ptr1);
}
x
Option: A
Explanation
Here function() gives the address of first value("ant") in an arr.This address is summationed by a sizeof(int) which is 4. now the address in ptr points the value eggs, which is then reduced by 2 . now it points to the value cat which is finally displayed
25. What will be the output of the C program?
#include<stdio.h>
int main()
{
struct node
{
int a, b, c;
};
struct node num = {3, 5, 6};
struct node *ptr = & num;
printf("%d\n", *((int*)ptr + 1 + (3-2)));
return 0;
}
x
Option: D
Explanation
Here the pointer variable stores the address of first value in struct node num = {3, 5, 6}; which is incremented by 2 and then the value 6 is finally displayed.
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