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Problems on Ages
Ages - Aptitude
1. Kumar's age after 15 years will be 5 times his age 5 years back. What is the present age of Kumar?
x
Option: B
Explanation
Consider Kumar's present age is X years
Kumar's age after 15 years = present age + 15 years = (X + 15)
Kumar's age 5 years back=present age - 5 years = (X - 5)
Kumar's age after 15 years will be 5 times his age 5 years back
i.e) 5(X - 5)
present age => X + 15 = 5(X - 5)
X + 15 = 5X - 25
4X = 40
i.e)X = 10
2. The ages of two persons differ by 14 years. If 4 years ago, the elder one be 3 times as old as the younger one, find their present ages.
x
Option: A
Explanation
Consider the age of younger person be X
ages of two person differ by 14 years. i.e) the age of elder person = X + 14
4 years ago the elder one age is 3 times older than younger one
i.e) age of elder one 4 years ago be (X + 14 - 4) = (X + 10) and younger one age at that time be (X - 4)
i.e) 3 (X - 4) = (X + 10)
3X - 12 = X + 10
2X = 22
younger one's present age X = 11 years
i.e) present age of elder one be (X + 14) = (11 + 14) = 25 years
3. The product of the ages of Swetha and Nikita is 240. If twice the age of Nikita is more than Swetha's age by 4 years, What is Nikita's age?
x
Option: D
Explanation
Let the swetha's age be X
as the product of swetha and nikita ages are 240. Nikita age will be
Twice the age of Nikita is more than swetha's age by 4 years.
i.e) 2 * (480 - X2= 4X
X2+4X-480=0
Reduce the equation into factors as (X + 24)(X - 20)
since X cannot be negative X = 20
Nikita's age
=(4. Ajay's age after 6 years will be three-seventh of his father's age. Ten years ago, the ratio of their ages was 1:5. What is ajay's father's age at present?
x
Option: B
Explanation
Considering the ratio's let the ages of ajay and his father 10 years ago be X and 5X Years
ajay's age after 6 Years = (X + 10) + 6 = X + 16 Years
Father's age after 6 years = (5X + 10) + 6 = 5X + 16 years
Ajay's age after 6 years will be three-seventh of his father's age
i.e) (X + 16) = 3 / 7(5X + 16)
7(X + 16) = 3(5X + 16)
7X + 112 = 15X + 48
8X = 64. i.e) X = 8
i.e) Ajay's father's present age = (5X + 10) = ((5 * 8) + 10) = 50 Years
5. One year ago, the ratio of Ajith's and Ashok's age was 6:7 respectively. Four years hence, this ratio would become 7:8. How old is Ashok?
x
Option: C
Explanation
Let Ajith's & Ashok's age 1 year ago be 6X and 7X Years(Considering the ratio's)
Ajith's and Ashok's present ages be (6X + 1) and (7X + 1) Years
Ajith age after 4 years = (6X + 1) + 4 = 6X + 5 Years
Ashok age after 4 years = (7X + 1) + 4 = 7X + 5 Years
after 4 years their ratio would be 7:8. i.e)
8(6X + 5) = 7( 7X + 5)
48X + 40 = 49X + 35
X = 5
i.e) Ashok's present age = (7X + 1) = ((7 * 5) + 1) = 36 years
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