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16.If the manufacturer gains 10%, the wholesale dealer 15% and the retailer 25%, then find the cost of production of a table, the retail price of which is Rs.1265?
Option: C
Consider the cost of production of the table be Rs.x
then, 125% of 115% of 110% of x = 1265
(125/100) * (115/100) * (110/100) * x = 1265
x = (1265 * 100 * 100 * 100)/(125 * 115 * 110) = Rs.800
17.Gopi purchased a pressure cooker at 9/10th of its selling price and sold it at 8% more than its S.P. Find her gain percent
Option: A
Consider the S.P. be Rs.x
C.P. = Rs.9x/10
Receipt = 108% of Rs.x = (108/100) * x = Rs.27x/25
gain = Rs.(27x/25) - (9x/10) = Rs.(108x - 90x)/100 = Rs.18x/100
gain% = (18x/100) * (10/9x) * 100 = 20%
18.An article is sold at a certain price. By selling it at 2/3 of that price one loses 10%. Find the gain percent at original price.
Option: D
Consider the original S.P. be Rs.x
then, new S.P. = Rs.2x/3
loss = 10%
C.P. = Rs.(100/90) * (2x/3) = Rs.20x/27
gain = Rs.(x - (20x/27)) = Rs.7x/27
gain% = (7x/27) * (27/20x) * 100 = 35%
19.A tradesman sold an article at a loss of 20%. If the selling price had been increased by Rs.100, there would have been a gain of 5%. What was the cost price of the article?
Option: A
Consider C.P. be Rs.x
then, (105% of x) - (80% of x) = 100
i.e) 25% of x = 100
25x/100 = 100
x = (100 * 100)/25 = 400
20.A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.10.50 less, he would have gained 30%. Find the cost price of the article.
Option: A
Consider the C.P. be Rs.x
1st S.P. = 125% of x = 125x/100 = 5x/4
2nd S.P. = 80% of x = 80x/100 = 4x/5
2nd S.P. = 130% of 4x/5 = (130/100) * (4x/5) = 26x/25
i.e) (5x/4) - (26x/25) = 10.50
21x/100 = 10.50
x = (10.50 * 100)/21 = Rs.50
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