Problems on Ages

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Problems on Average

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Permutation and Combination

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Problems on Probability

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Problems on Test Divisibility

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Time and Work

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Solved Problems on Ages

Ages - Aptitude

16. The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages:

A. 5:2✘

B. 9:2✘

C. 13:4✘

D. 7:3✔

x

 

Option: D

Explanation

Let the age of son be x years

Then the age of father will be 3x years

then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40 i.e) x = 20

Ratio = (3x + 10) : (x+10) = 70:30

i.e) Required Ratio = 7:3

✉ Answer

17. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of his son. After 6 years, son's age will be:

A. 20 years✔

B. 18 years✘

C. 16 years✘

D. 14 years✘

x

 

Option: A

Explanation

Let the present age of son be x years

Then the present age of father will be 60 - x years

Six years ago, father's age was five times the age of his son

Then (60 - x) - 6 = 5(x - 6)

54 - x = 5x - 30

6x = 84, i.e) x = 14

i.e) Son's age after 6 years = (x + 6) = (14 + 6) = 20 years

✉ Answer

18. Suresh's grandfather was 8 times older to him 16 years ago. He would be 3 times of his age 8 years from now. Eight years ago, what was the ratio of Suresh's age to that of his grandfather?

A. 1:2✘

B. 1:5✘

C. 3:8✘

D. None of these✔

x

 

Option: D

Explanation

16 years ago let Suresh age = x years and grandfather age = 8x years

After 8 years from now, T = (x + 16 + 8) years and grandfather age = (8x + 16 + 8) years

i.e) 8x + 24 = 3(x + 24)

5x = 48 i.e) x =

48
5

Ratio of their ages 8 years ago =

x + 8
8x + 8

=>

48
5
+8
8*
48
5
+8
=
88
424
=
11
53

✉ Answer

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