Problems on Ages

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Problems on Average

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Odd Man Out Series

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Problems on Percentage

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Permutation and Combination

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Problems on Probability

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Problems on Profit Loss

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Problems on Test Divisibility

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Time and Work

Time and Work - 1 Time and Work - 2 Time and Work - 3

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- Steve Jobs

Tricky Questions on Ages

Ages - Aptitude

11. The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

x

Option: B

Explanation

Consider the ages of 5 children be X, (X + 3), (X + 6), (X + 9) and (X + 12) years

sum of 5 children is 50

then, X + (X + 3) + (X + 6) + (X + 9) + (X + 12) = 50

5X + 30 = 50

5X = 20

X = 4

i.e) Age of the youngest child = 4 years.

12. Prabhu got married 8 years ago. His present age is

6

5

times his age at the time of his marriage. Prabhu's sister was 10 years younger to him at the time of his marriage. The age of Prabhu's sister is:

x

Option: A

Explanation

Consider Prabhu's present age be X years

then, his age at the time of marriage = (X - 8) years

now, X =

6

5

(X - 8)

5X = 6X - 48

X = 48

Prabhu's sister's age at the time of his marriage = (X - 8) - 10 = (X - 18) = (48 - 18) = 30 years

i.e) Prabhu's sister's present age = (30 + 8) years = 38 years

13. A is much younger than B as he is older than C. If the sum of the ages of B and C is 50 years, What is definitely the difference between B and A's age?

A. Data Inadequate✔

x

Option: A

Explanation

A is much younger than B i.e) B-A

B is older than c i.e) B - C

From above 2 expressions (B - A) = (B - C) i.e) A = C

also sum of B and C is 50 years i.e) B + C = 50 years

i.e) B + A = 50 years(since A = C)

so, B - A cannot be determined

so, Data Inadequate

14. The total age of D and E is 12 years more than the total age of E and F. F is how many years younger than D?

D. None of these✘

x

Option: B

Explanation

total age of D&E is 12 years more than total age of E&F

i.e) (D + E) - (E + F) = 12

then, D - F = 12

i.e) F is younger than D by 12 years

15. The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

A. 20, 35, 45✘

B. 8, 20, 28✘

C. 16, 28, 36✔

D. None of these✘

x

Option: C

Explanation

Consider their present ages be 4X, 7X and 9X years

8 years ago sum of their ages is 56

i.e. (4X - 8) + (7X - 8) + (9X - 8) = 56

20X = 80

X = 4

the present ages are (4 * 4), (7 * 4), and (9 * 4)

i.e. the present ages are16 years, 24 years and 36 years

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